Chapter 9: Mechanical Properties of Fluids
Unit VII – Properties of Bulk Matter
9.1 Pressure
Pressure is the normal force per unit area exerted by a fluid:
\[ P = \frac{F}{A} \]
- SI unit: Pascal (Pa) = N/m²
- Atmospheric pressure: \(P_0 = 1.013 \times 10^5 \text{ Pa}\)
Pressure at depth h in a fluid of density \(\rho\):
\[ P = P_0 + \rho g h \]
9.2 Pascal’s Law
Pressure applied to an enclosed fluid is transmitted unchanged to every point of the fluid and the walls of the container.
Hydraulic lift:
\[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \Rightarrow F_2 = F_1 \cdot \frac{A_2}{A_1} \]
A small force on a small piston creates a large force on a large piston.
9.3 Buoyancy and Archimedes’ Principle
Any object fully or partially submerged in a fluid experiences an upward buoyant force equal to the weight of the displaced fluid.
\[ F_{buoy} = \rho_{fluid} \cdot V_{displaced} \cdot g \]
Condition for floating: \(\rho_{object} \leq \rho_{fluid}\)
9.4 Viscosity
Viscosity is the internal friction of a fluid that resists flow.
Newton’s law of viscosity:
\[ F = -\eta A \frac{dv}{dy} \]
where \(\eta\) is the coefficient of viscosity (SI unit: Pa·s or N·s/m²)
Stokes’ Law: Drag force on a sphere of radius \(r\) moving with velocity \(v\):
\[ F = 6\pi\eta r v \]
Terminal velocity:
\[ v_T = \frac{2r^2(\rho - \rho_0)g}{9\eta} \]
where \(\rho\) = density of sphere, \(\rho_0\) = density of fluid.
9.5 Streamline and Turbulent Flow
- Streamline flow: Each layer of fluid flows smoothly; velocity at every point is constant in time.
- Turbulent flow: Irregular, chaotic motion with eddies and whirls.
Reynolds number determines type of flow:
\[ R_e = \frac{\rho v D}{\eta} \]
- \(R_e \lt 1000\): Streamline
- \(R_e \gt 2000\): Turbulent
Equation of Continuity (for incompressible fluid):
\[ A_1 v_1 = A_2 v_2 \]
9.6 Bernoulli’s Theorem
For steady, incompressible, non-viscous flow, the total energy per unit volume is constant along a streamline.
\[ P + \frac{1}{2}\rho v^2 + \rho g h = \text{constant} \]
9.7 Bernoulli’s Principle – Diagram
Applications of Bernoulli’s theorem:
- Aircraft wings (lift)
- Carburetor
- Spray gun, Bunsen burner
- Speed of efflux: \(v = \sqrt{2gh}\) (Torricelli’s theorem)
9.8 Surface Tension
Surface tension (T) is the force per unit length acting along the surface of a liquid:
\[ T = \frac{F}{l} \]
SI unit: N/m
Surface energy: Energy per unit area = \(T\) (numerically)
Excess Pressure
- Inside a liquid drop: \(\Delta P = \dfrac{2T}{r}\)
- Inside a soap bubble: \(\Delta P = \dfrac{4T}{r}\) (two surfaces)
Capillary Rise
\[ h = \frac{2T\cos\theta}{\rho g r} \]
where \(\theta\) = contact angle, \(r\) = radius of capillary.
Key Formulas Summary
| Formula | Quantity |
|---|---|
| \(P = P_0 + \rho gh\) | Pressure at depth h |
| \(F_b = \rho_{fluid} V g\) | Buoyant force |
| \(v_T = \dfrac{2r^2(\rho-\rho_0)g}{9\eta}\) | Terminal velocity |
| \(P + \frac{1}{2}\rho v^2 + \rho gh = \text{const}\) | Bernoulli’s theorem |
| \(h = \dfrac{2T\cos\theta}{\rho g r}\) | Capillary rise |
Practice Questions
Section A – MCQ (1 mark each)
Q1. Bernoulli’s theorem applies to:
(a) Viscous flow (b) Turbulent flow (c) Steady, non-viscous flow (d) All flows
Answer
(c) Steady, non-viscous, incompressible flow
Q2. A ball falls through a viscous fluid and reaches terminal velocity. At this point:
(a) Net force is maximum (b) Acceleration is 9.8 m/s² (c) Net force is zero (d) Velocity is increasing
Answer
(c) Net force is zero — at terminal velocity, drag + buoyancy = weight.
Section B – Short Answer (2–3 marks)
Q3. Water flows through a pipe of cross-section 8 cm² at a speed of 3 m/s. It enters a narrower pipe of cross-section 2 cm². Find the speed in the narrow pipe.
Answer
By continuity: \(A_1 v_1 = A_2 v_2\)
\(v_2 = \dfrac{A_1 v_1}{A_2} = \dfrac{8 \times 10^{-4} \times 3}{2 \times 10^{-4}} = \mathbf{12 \text{ m/s}}\)
Section D – Competency-Based Questions
Q4. (Case Study) Water in a dam is at height 20 m above a hole at the bottom.
(i) Find the speed at which water exits the hole (Torricelli’s theorem).
(ii) If the hole has area \(10^{-4}\) m², find the volume flow rate.
(iii) State two real-world applications of Bernoulli’s theorem.
(\(g = 10 \text{ m/s}^2\))
Answer
(i) \(v = \sqrt{2gh} = \sqrt{2 \times 10 \times 20} = \sqrt{400} = \mathbf{20 \text{ m/s}}\)
(ii) \(Q = Av = 10^{-4} \times 20 = \mathbf{2 \times 10^{-3} \text{ m}^3/\text{s}}\)
(iii)
- Aircraft lift — air moves faster over the curved upper wing surface → lower pressure → net upward force.
- Spray atomizer — fast-moving air over narrow tube creates low pressure → liquid is sucked up and sprayed.