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Chapter 9: Mechanical Properties of Fluids

Unit VII – Properties of Bulk Matter


9.1 Pressure

Pressure is the normal force per unit area exerted by a fluid:

\[ P = \frac{F}{A} \]

  • SI unit: Pascal (Pa) = N/m²
  • Atmospheric pressure: \(P_0 = 1.013 \times 10^5 \text{ Pa}\)

Pressure at depth h in a fluid of density \(\rho\):

\[ P = P_0 + \rho g h \]


9.2 Pascal’s Law

Pressure applied to an enclosed fluid is transmitted unchanged to every point of the fluid and the walls of the container.

Hydraulic lift:

\[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \Rightarrow F_2 = F_1 \cdot \frac{A_2}{A_1} \]

A small force on a small piston creates a large force on a large piston.


9.3 Buoyancy and Archimedes’ Principle

Any object fully or partially submerged in a fluid experiences an upward buoyant force equal to the weight of the displaced fluid.

\[ F_{buoy} = \rho_{fluid} \cdot V_{displaced} \cdot g \]

Condition for floating: \(\rho_{object} \leq \rho_{fluid}\)


9.4 Viscosity

Viscosity is the internal friction of a fluid that resists flow.

Newton’s law of viscosity:

\[ F = -\eta A \frac{dv}{dy} \]

where \(\eta\) is the coefficient of viscosity (SI unit: Pa·s or N·s/m²)

Stokes’ Law: Drag force on a sphere of radius \(r\) moving with velocity \(v\):

\[ F = 6\pi\eta r v \]

Terminal velocity:

\[ v_T = \frac{2r^2(\rho - \rho_0)g}{9\eta} \]

where \(\rho\) = density of sphere, \(\rho_0\) = density of fluid.


9.5 Streamline and Turbulent Flow

  • Streamline flow: Each layer of fluid flows smoothly; velocity at every point is constant in time.
  • Turbulent flow: Irregular, chaotic motion with eddies and whirls.

Reynolds number determines type of flow:

\[ R_e = \frac{\rho v D}{\eta} \]

  • \(R_e \lt 1000\): Streamline
  • \(R_e \gt 2000\): Turbulent

Equation of Continuity (for incompressible fluid):

\[ A_1 v_1 = A_2 v_2 \]


9.6 Bernoulli’s Theorem

For steady, incompressible, non-viscous flow, the total energy per unit volume is constant along a streamline.

\[ P + \frac{1}{2}\rho v^2 + \rho g h = \text{constant} \]


9.7 Bernoulli’s Principle – Diagram

Bernoulli's Principle – Venturi Effect v₁ (slow) v₂ (fast) v₁ P₁ (High) P₂ (Low) P₁ (High) Wide section A₁, v₁, P₁ Narrow: A₂<A₁ v₂>v₁, P₂<P₁ P + ½ρv² + ρgh = constant | High speed → Low pressure

Applications of Bernoulli’s theorem:

  • Aircraft wings (lift)
  • Carburetor
  • Spray gun, Bunsen burner
  • Speed of efflux: \(v = \sqrt{2gh}\) (Torricelli’s theorem)

9.8 Surface Tension

Surface tension (T) is the force per unit length acting along the surface of a liquid:

\[ T = \frac{F}{l} \]

SI unit: N/m

Surface energy: Energy per unit area = \(T\) (numerically)

Excess Pressure

  • Inside a liquid drop: \(\Delta P = \dfrac{2T}{r}\)
  • Inside a soap bubble: \(\Delta P = \dfrac{4T}{r}\) (two surfaces)

Capillary Rise

\[ h = \frac{2T\cos\theta}{\rho g r} \]

where \(\theta\) = contact angle, \(r\) = radius of capillary.


Key Formulas Summary

FormulaQuantity
\(P = P_0 + \rho gh\)Pressure at depth h
\(F_b = \rho_{fluid} V g\)Buoyant force
\(v_T = \dfrac{2r^2(\rho-\rho_0)g}{9\eta}\)Terminal velocity
\(P + \frac{1}{2}\rho v^2 + \rho gh = \text{const}\)Bernoulli’s theorem
\(h = \dfrac{2T\cos\theta}{\rho g r}\)Capillary rise

Practice Questions

Section A – MCQ (1 mark each)

Q1. Bernoulli’s theorem applies to:

(a) Viscous flow   (b) Turbulent flow   (c) Steady, non-viscous flow   (d) All flows

Answer

(c) Steady, non-viscous, incompressible flow


Q2. A ball falls through a viscous fluid and reaches terminal velocity. At this point:

(a) Net force is maximum   (b) Acceleration is 9.8 m/s²   (c) Net force is zero   (d) Velocity is increasing

Answer

(c) Net force is zero — at terminal velocity, drag + buoyancy = weight.


Section B – Short Answer (2–3 marks)

Q3. Water flows through a pipe of cross-section 8 cm² at a speed of 3 m/s. It enters a narrower pipe of cross-section 2 cm². Find the speed in the narrow pipe.

Answer

By continuity: \(A_1 v_1 = A_2 v_2\)

\(v_2 = \dfrac{A_1 v_1}{A_2} = \dfrac{8 \times 10^{-4} \times 3}{2 \times 10^{-4}} = \mathbf{12 \text{ m/s}}\)


Section D – Competency-Based Questions

Q4. (Case Study) Water in a dam is at height 20 m above a hole at the bottom.

(i) Find the speed at which water exits the hole (Torricelli’s theorem).

(ii) If the hole has area \(10^{-4}\) m², find the volume flow rate.

(iii) State two real-world applications of Bernoulli’s theorem.

(\(g = 10 \text{ m/s}^2\))

Answer

(i) \(v = \sqrt{2gh} = \sqrt{2 \times 10 \times 20} = \sqrt{400} = \mathbf{20 \text{ m/s}}\)

(ii) \(Q = Av = 10^{-4} \times 20 = \mathbf{2 \times 10^{-3} \text{ m}^3/\text{s}}\)

(iii)

  1. Aircraft lift — air moves faster over the curved upper wing surface → lower pressure → net upward force.
  2. Spray atomizer — fast-moving air over narrow tube creates low pressure → liquid is sucked up and sprayed.